Answer:
32.66 m/s
Explanation:
[tex]k=30000N/m\\x=4 cm=0.04 m\\m=45g=0.045kg[/tex]
The potential energy stored in the spring will impart kinetic energy into the dart:
[tex]\frac{1}{2}kx^2=\frac{1}{2}mv^2\\v=\sqrt{\frac{k}{m}}x[/tex]
substitute the values:
[tex]v=\sqrt{\frac{30000}{0.045}}\times0.0=32.66m/s[/tex]
