Respuesta :
Explanation:
Oxidation number is defined as the number holded by an atom by either gain or loss of electrons when it chemically combines with another atom.
Oxidation number of each atom in the given compounds is as follows.
(a) [tex]H_{2}O_{2}[/tex]
Oxidation number of hydrogen is +1 so, the oxidation number of oxygen in [tex]H_{2}O_{2}[/tex] is as follows.
2(+1) + 2x = 0
x = -1
So, oxidation number of H is +1 and O is -1.
(b) [tex]ClO^{-}_{3}[/tex]
Oxidation number of oxygen is -2. So, oxidation number of chlorine is calculated as follows.
x + 3(-2) = -1
x = +5
Hence, the oxidation number of Cl is +5 and O is -2.
(c) [tex]H_{2}SO_{4}[/tex]
Oxidation number of hydrogen is +1 and oxygen is -2. Now, we will calculate the oxidation number of sulfur as follows.
2(+1) + x + 4(-2) =0
2 + x -8 = 0
x = +6
Hence, the oxidation number of H is +1, S is +6 and O is -2.
There are ways to assign oxidation numbers. The answer is given below;
- The oxidation numbers for H2O2
The oxidation number of O in H2O2 is known to be -2,
but O is -1 if it is a peroxides.
The oxidation number of H is known as +1. Based on the fact that there are two H atoms, the sum is +2. H2O2 is said to have no charge.
Therefore, the oxidation number of each atom in H2O2 H are +1 and O is -1.
- In the chlorate ion (ClO3-), the oxidation number of Cl is known to be+5. The oxidation number of O present here is -2.
Therefore the oxidation number of each atom in ClO3− are Cl is +5 and O is -2.
- In H2SO4 , hydrogen is known to be found in +1 state, and oxygen is found in −2 state while, sulfur is found in the +6 state.
Therefore the oxidation number of each atom in H2SO4 are H is +1, S is +6 and O is -2.
What is meant by oxidation number?
The oxidation number is known to be the total amount of electrons that an atom is known to gains or loses so as to create a chemical bond with another kind of atom.
In the oxidation number method, you can know or assign the oxidation numbers of all atoms.
Learn more about oxidation numbers from
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