Respuesta :

Answer:

The answer is [tex]x^2-(2+3i)x+6i[/tex]

Step-by-step explanation:

The polynomial with zeros 2 and 3i must have factors [tex](x-2)[/tex] and [tex](x-3i)[/tex] so the polynomial is

[tex](x-2)(x-3i)=x^2-(2+3i)x+6i[/tex]