Answer:
1 ⇒ A
2 ⇒ B
3 ⇒ D
4 ⇒ C
Explanation:
We use the Freezing point depression to solve this:
Freezing T° pure solvent - Freezing T° of solution = Kf . m . i
1. Potassium acetate:
0°C - Freezing T° of solution = 1.86°C/m . 0.24m . 2
KCH₃COO → K⁺ + CH₃COO⁻ i = 2
Freezing T° of solution = -1.49°C (A)
2. Aluminum nitrate:
0°C - Freezing T° of solution = 1.86°C/m . 0.11m . 4
Al(NO₃)₃ → Al³⁺ + 3NO₃⁻ i= 4
Freezing T° of solution = -0.82°C (B)
3. Chromium (II) nitrate
0°C - Freezing T° of solution = 1.86°C/m . 0.13m . 3
Cr(NO₃)₂ → Cr²⁺ + 2NO₃⁻ i= 3
Freezing T° of solution = - 0.72°C (D)
4. Ethylene glycol(nonelectrolyte) → I = 1
0°C - Freezing T° of solution = 1.86°C/m . 0.41m . 1
Freezing T° of solution = - 0.76°C (C)
