Answer:
Numerical value of [tex]K_{c}[/tex] is 242
Explanation:
[tex]K_{c}[/tex] for the given reaction is represented as-
[tex]K_{c}=\frac{[SO_{3}]^{2}}{[SO_{2}]^{2}[O_{2}]}[/tex]
Where species inside third bracket represent equilibrium concentrations.
Here, [tex][SO_{3}]=0.66M[/tex] , [tex][SO_{2}]=0.10M[/tex] and [tex][O_{2}]=0.18M[/tex]
Plug-in all the given values in the above equation-
[tex]K_{c}=\frac{(0.66)^{2}}{(0.10)^{2}\times (0.18)}[/tex]
[tex]=242[/tex]
So, numerical value of [tex]K_{c}[/tex] is 242
