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Declare a variable named pump number as an integer type. Test if it is within the following range: Greater and equal to 1 and smaller and equal to 10, if it is, multiple its value by 13. Now test if it is an even number, if it is, deliver a message to the user, "it is a bad number!". If the pump number is not in the range described above, then deliver a message to user, "out of range value!"

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Answer:

Following are the program in C++ Language.

#include <iostream> // header file

using namespace std; // namespace

int main() // main function

{

   int pump; // variable declaration

   cout<<"Enter the number: ";

   cin>>pump;// Read the value by the user

   if( (pump >= 1) &&(pump <= 10))// checking condition

           pump=pump* 13 ;

           if(pump % 2 == 0)// checking condition

        cout<<" it is a bad number!";

           else

           cout<<" out of range value!";

   return(0);

   

}

Output:

Enter the number:4

it is a bad number!

Explanation:

Following are the Description of the following statements.

  • Declared a variable "pump" vaiable of int type.
  • Read the number by the user by using cin function.
  • Check the condition if( (pump >= 1) &&(pump <= 10)) then it executed the if statements block.
  • Inside this if there is also one another i.e nested if
  • if(pump % 2 == 0) if this statement then it executed the statement inside if otherwise else block will be executed