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Let's consider a jar consists of 20 marbles. 12 are red and 8 are green. John picked 2 marbles at random. What is the probability that John picked both the marbles red assuming that the first one is not replaced?

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tramserran

Answer:   [tex]\bold{\dfrac{33}{95}}[/tex]

Step-by-step explanation:

First pick    and      Second pick      =  Probability

    [tex]\dfrac{12\ red}{20\ total}\quad \times[/tex]    [tex]\dfrac{11\ red\ remaining}{19\ total\ remaining}\\[/tex]  [tex]=\dfrac{132}{380}\\[/tex]  

    Simplify:

 [tex]\dfrac{132}{380}\div \dfrac{4}{4}=\large\boxed{\dfrac{33}{95}}\\[/tex]

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