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A stubborn, 100 kgkg mule sits down and refuses to move. To drag the mule to the barn, the exasperated farmer ties a rope around the mule and pulls with his maximum force of 800 NN . The coefficients of friction between the mule and the ground are μsμsmu_s = 0.80 and μk=0.5μk=0.5.

Is the farmer able to move the mule?

Respuesta :

lublana

Answer:

No, the farmer is not able to move the mule.

Explanation:

Mass =100 kg

Force=F=800 N

The coefficient between the mule and the ground=[tex]\mu_s=0.8[/tex]

[tex]\mu_k=0.5[/tex]

Static friction force,f=[tex]\mu N[/tex]

Normal force=N=mg

Static friction force,f=[tex]\mu_s mg=0.8\times 100\times 9.8=784 N[/tex]

Using [tex]g=9.8m/s^2[/tex]

F<f

Static friction force is greater than applied force.

Therefore , the farmer is not able to move the mule.

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