If the variance is 28 kg2 what is the standard deviation?

Answer:
The standard deviation is 5.29 kg.
Step-by-step explanation:
The standard deviation is the square root of the variance. Mathematically, we have that:
[tex]S(X) = \sqrt{V(X)}[/tex]
In this problem, we have that:
[tex]V(X) = 28[/tex]
So
[tex]S(X) = \sqrt{V(X)}[/tex]
[tex]S(X) = \sqrt{28}[/tex]
[tex]S(X) = 5.29[/tex]
The standard deviation is 5.29 kg.