Answer:
Step-by-step explanation:
Given that the position vector of a moving body at time t is
[tex]r(t) = (3t ^6,6t - 5,2 + 3t), t\geq 0[/tex]
Velocity is the derivative of acceleration
v(t) = [tex](18t^5, 6, 3)[/tex], t positive
Speed would be the magnitude of the velocity and will not have direction
Speed = [tex]\sqrt{324t^{10}+36+9 } \\=\sqrt{324t^{10}+45)[/tex]
Acceleration of the object
a(t) = derivative of velocity of vector
= [tex](90t^4, 0,0)[/tex]
i.e. acceleration would be in the direction of x axis alone.
