Respuesta :
Answer:
The intensity level is 77.5 dB.
(a) is correct option.
Explanation:
Given that,
Distance [tex]r_{1}= 15.0\ m[/tex]
Distance [tex]r_{2}= 2.0\ m[/tex]
Intensity level = 60.0 dB
We know that,
[tex]I=\dfrac{P}{A}[/tex]
[tex]I=\dfrac{P}{4\pi r^2}[/tex]
Here, Intensity is inversely proportional to the square of the distance.
[tex]I\propto\dfrac{1}{r^2}[/tex]
We need to calculate the intensity level
Using formula of intensity level
[tex]B=10 dB\log(\dfrac{I}{I_{0}})[/tex]
Now,
[tex]B_{2}-B_{1}=10 dB\log(\dfrac{I_{2}}{I_{1}})[/tex]
Put the value of intensity
[tex]B_{2}-B_{1}=10 dB\log(\dfrac{r_{1}^2}{r_{2}^2})[/tex]
[tex]B_{2}=B_{1}+10 dB\log(\dfrac{r_{1}^2}{r_{2}^2})[/tex]
[tex]B_{2}=60 dB +10 dB\log(\dfrac{15^2}{2^2})[/tex]
[tex]B_{2}=77.5\ dB[/tex]
Hence, The intensity level is 77.5 dB.
The intensity level of the source of sound at the point has a distance of 2.00 m in case the radiation spreads in equivalent directions would be:
a). 77.5 dB
Given that,
[tex]d_{1}[/tex] [tex]= 15.0 m[/tex]
[tex]d_{2} = 2.0 m[/tex]
The level of intensity [tex]= 60.0 dB[/tex]
As we know,
[tex]I = P/A[/tex]
⇒ [tex]I = P/[/tex]4π[tex]r^{2}[/tex]
We can see that the association between the distance's square would be reciprocally proportional.
[tex]B = 10dBlog[/tex]([tex]I_{}/ I_{0}[/tex])
so,
[tex]B = I_{2}/ I_{1}[/tex]
Now after putting the value of intensity would be:
[tex]B_{2}- B_{1}[/tex] [tex]= 10 dB log (r^{2}_{1}/r^{2}_{2})[/tex]
⇒ [tex]B_{2} = 60dB + 10dB log (15^2/2^2)[/tex]
∵ [tex]B_{2} = 77.5 dB[/tex]
Thus, option a is the correct answer.
Learn more about 'Directions' here:
brainly.com/question/17238121
