Calculate the amount of heat released when 27.0 g H2O is cooled from a liquid at 314 K to a solid at 263 K. The melting point of H2O is 273 K. Other useful information about water is listed below.

Cp,liquid = 4.184 J/(g•K)

Cp,solid = 2.093 J/(g•K)

ΔHfusion = 40.7 kJ/mol

Respuesta :

Cool liquid from 314 K to 273 K, freeze liquid at 273 K, and cool solid to 263 K.

The amount of heat released in the given situation would be as follows:

[tex]-66.2 KJ[/tex]

Given that,

Weight of [tex]H2O[/tex] [tex]= 27g[/tex]

The Temperature of the Liquid [tex]= 314 k[/tex]

The Temperature of the Solid [tex]= 263 K[/tex]

Melting point of [tex]H2O = 273 K[/tex]

To find,

The amount of heat released = [tex][Q[/tex] × [tex]C_{p}l[/tex] ×[tex](T_{final} - T_{Initial} ) +[/tex] Δ [tex]Hfusion + [m[/tex] × [tex]C_{p}s[/tex] × [tex]T_{final} - T_{Initial} ][/tex]

By putting the values in the above formula,

∵ Heat released = [tex]-66.2 KJ[/tex]

Learn more about "Melting Point" here:

brainly.com/question/5753603

Ver imagen JackelineCasarez