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A current of 9 A flows through an electric device with a resistance of 43 Ω. What must be the applied voltage in this particular circuit?

Respuesta :

Edufirst
Ohm's law:

V = R . I

V = 43 ohms × 9 A = 387 volts
AlpenGlow

The answer would be:

387 V

Just remember Ohm's Law:

V = IR

Where:

V = Voltage (V)

I = Current (A)

R = Resistance (Ω)

Our given is the following:

I = 9 A

R = 43 Ω

Now all you need to do is plug in all the values:

V = IR

V = (9A)(43Ω)

V = 387 V

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