Answer: 2800 calories
Explanation:
Latent heat of fusion is the amount of heat required to convert 1 mole of solid to liquid at atmospheric pressure.
Amount of heat required to fuse 1 gram of water = 80 cal
Mass of ice given = 35 gram
Heat required to fuse 1 g of ice at [tex]0^0C[/tex] = 80 cal
Thus Heat required to fuse 35 g of ice =[tex]\frac{80}{1}\times 35=2800cal[/tex]
Thus 2800 calories of energy is required to melt 35 g ice cube
