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In a population of 1000 snails, tests of snail color genes show that 160 snails are AA, 480 are Aa and 360 are aa. What is the frequency of the A allele in this population? .04 .1 .6 .4 .001

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Answer:

Option C.

Step-by-step explanation:

Total population = 1000 snails

AA = 160 snails

Aa = 480 snails

aa = 360 snails

Frequency of each type.

[tex]AA=\dfrac{160}{1000}=0.16[/tex]

[tex]Aa=\dfrac{480}{1000}=0.48[/tex]

[tex]aa=\dfrac{360}{1000}=0.36[/tex]

Now, we get

[tex]A^2=0.16\Rightarrow A=\sqrt{0.16}=0.4[/tex]

he frequency of the A allele in this population is 0.4.

Therefore, the correct option is C.

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