Answer:
[tex]-0.82i+0.57j[/tex]
Step-by-step explanation:
We are given that a unit vector A which lies in the xy-plane.
Unit vector:It is that vector whose magnitude is equal to 1.
[tex]\mid A\mid=1[/tex]
[tex]\theta=145^{\circ}[/tex]
We have to find the unit vector.
x-component of unit vector=[tex]A_x=\mid A\mid cos\theta[/tex]
x-component of unit vector=[tex]A_x=1cos145^{\circ}=-0.82[/tex]
y-component of unit vector=[tex]A_y=\mid A\mid sin\theta=1\times sin145=0.57[/tex]
Unit vector ,A=[tex]A_xi+A_yj=-0.82i+0.57j[/tex]
Hence, the unit vector =[tex]A=-0.82i+0.57j[/tex]
