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Suppose the pilot makes an emergency turn to avoid an approaching missile, subjecting himself to a centripetal acceleration of 10 gs, while flying at 670 m/s (supersonic). What is the radius, in km, of his turn? (This must be short-lived because fighter planes can only briefly endure such large accelerations without serious damage, and the pilot will soon black out at 10 gs.)

Respuesta :

Answer:

  R = 4580.61 m

Explanation:

given,

Speed of the flight, v = 670 m/s

centripetal acceleration, a_c = 10 g

                                         = 10 x 9.8 = 98 m/s²

Radius of his turn, R = ?

using centripetal acceleration

[tex]a_c = \dfrac{v^2}{R}[/tex]

[tex]R = \dfrac{v^2}{a_c}[/tex]

[tex]R = \dfrac{670^2}{98}[/tex]

  R = 4580.61 m

Hence, The radius of the turn of the flight is equal to 4580.61 m.

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