Answer:
Energy of one mole of photon will be [tex]2.89\times 10^5J[/tex]
Explanation:
We have given wavelength of photon [tex]\lambda =413nm=413\times 10^{-9}m[/tex]
Velocity of light is given [tex]c=3\times 10^8m/sec[/tex]
Plank's constant [tex]h=6.626\times 10^{-34}Js[/tex]
Energy of the photon is given by [tex]E=\frac{hc}{\lambda }=\frac{6.626\times 10^{-34}\times 3\times 10^8}{413\times 10^{-9}}=0.048\times 10^{-17}J[/tex]
We have to find the energy of one mole of photon
One mole of photon is equal to [tex]6.023\times 10^{23}photon[/tex]
So energy of one mole of photon will be equal to [tex]6.023\times 10^{23}\times 0.048\times 10^{-17}=2.89\times 10^5J[/tex]
So energy of one mole of photon will be [tex]2.89\times 10^5J[/tex]