The average ages of three persons 27 years. Their ages are in the proportion of 1:3:5. what is the age in years of the youngest one among them ?​

Respuesta :

Answer:

9 years old

Step-by-step explanation:

the average age of 3 people is 27

x / 3 = 27.....x = 27 * 3.....x = 81......this means that the total of their ages is 81.

their ages are in the proportion of 1:3:5....added = 9

this means that the first person is 1/9 of the total ages..

the second person is 3/9 of the total ages

the third person is 5/9 of the total ages

person 1 : 1/9 of 81 = 81/9 = 9 years old <==== this is the youngest

person 2 : 3/9 of 81 = 243/9 = 27 years old

person 3 : 5/9 of 81 = 405/9 = 45 years old

From the given average age of three persons, the age of the youngest one among them is equal to [tex]9[/tex] years.

What is average?

" Average is defined as the ratio of the sum of all the given quantity to the number of given quantity."

Formula used

Average [tex]= \ \frac { 1 }{n} \sum _ { } { } x_ {i} \)[/tex]

[tex]n=[/tex] number of given quantity

[tex]\sum_{}{}x_{i} =[/tex] sum of all the given quantity

According to the question,

Number of persons [tex]= 3[/tex]

Average ages of three person [tex]= 27[/tex]

Substitute the value in the formula we get,

[tex]27 = \frac{\sum _ {}{}x_{i}}{3}\\ \\\implies \sum _ {}{}x_{i}}= 27 \times 3\\\\\implies \sum _ {}{}x_{i}}= 81[/tex]

Proportion of the ages of three person [tex]= 1: 3: 5[/tex]

[tex]'x'[/tex] represents the age

As per given condition of average age we get,

[tex]x + 3x + 5x = 81\\\\\implies 9x = 81\\\\\implies x = 9[/tex]

Age of first person [tex]1x = 9 \ years[/tex]

Age of second person [tex]3x = 27 \ years[/tex]

Age of third person [tex]5x =45 \ years[/tex]

Hence ,as per given average age of youngest person is equal to [tex]9 \ years[/tex].

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