Answer:
[tex]a_{acceleriation}=-4cm/s^{2}\\ or\\ a_{acceleriation}=-0.04m/s^{2}[/tex]
Explanation:
Given data
velocity v₀=20 cm/s at time t=3s
velocity vf=0 at time t=8 s
To find
Average Acceleration at time=3s to 8s
Solution
As we know that acceleration is first derivative of velocity with respect to time
[tex]a_{acceleriation} =\frac{dv_{velocity}}{dt_{time}}\\a_{acceleriation} =\frac{v_{f}-v_{o} }{dt}\\ a_{acceleriation} =\frac{0-20cm/s }{8s-3s}\\ a_{acceleriation}=-4cm/s^{2}\\ or\\ a_{acceleriation}=-0.04m/s^{2}[/tex]
