An open box is to be constructed from a square piece of sheet metal by removing a square of side 4 feet from each corner and turning up the edges. If the box is to hold 576 cubic feet, what should be the dimensions of the sheet metal?

Given that an open box is to be constructed from a square piece of sheet metal by removing a square of side 4 feet from each corner and turning up the edges

Let a be the side of the square

When 4 feet is cut from each corner, and made into a box the dimensions would be a-8, a-8 and 4.

Volume of box = lwh

[tex]= (a-8) (a-8) 4[/tex]

This is equal to 576

[tex](a-8) (a-8) 4=576\\2(a-8) =24\\a-8 =12\\a=20[/tex]

Dimensions of the sheet should be 20x20 feet

An open box is to be constructed from a square piece of sheet metal by removing a square of side 4 feet from each corner and turning up the edges. If the box is to hold 576 cubic​ feet, what should be the dimensions of the sheet​ metal?

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An open box is to be constructed from a square piece of sheet metal by removing a square of side 4 feet from each corner and turning up the edges. If the box is to hold 576 cubic feet, what should be the dimensions of the sheet metal?