Vector A with arrow has x and y components of -8.60 cm and 18.0 cm, respectively; vector B with arrow has x and y components of 12.8 cm and -6.80 cm, respectively. If A with arrow - B with arrow + 3C with arrow = 0, what are the components of C with arrow?

Respuesta :

Answer: (a,b)= (7.13 ,-8.27)

Step-by-step explanation:

From the data, we have

A-B+3C=0

where, A= (-8.6, 18.0)

B= (12.8, -6.8)

and let C= (a, b)

So, putting values

(-8.6, 18.0) - (12.8, -6.8) + 3(a,b)=0

3(a,b) + (-21.4, 24.8) = 0

3(a,b)= (21.4, -24.8)

(a,b)= (7.13 ,-8.27)

In this exercise we have to use the knowledge of vectors to calculate the components of C, in this way we can say that:

[tex](a,b)= (7.13 ,-8.27)[/tex]

From the data, we have:

[tex]A-B+3C=0[/tex]

where,

  • [tex]A= (-8.6, 18.0)[/tex]
  • [tex]B= (12.8, -6.8)[/tex]

Computing the component of C, we find:

[tex](-8.6, 18.0) - (12.8, -6.8) + 3(a,b)=0\\ 3(a,b) + (-21.4, 24.8) = 0\\ 3(a,b)= (21.4, -24.8)\\ (a,b)= (7.13 ,-8.27)[/tex]

See more about vectores at brainly.com/question/13188123