Answer:
Time taken by ball to reach the ground will be equal to 4.74 second
So option (C) will be correct answer
Explanation:
It is given that ball is dropped from rest so initial velocity of ball u = 0 m/sec
Height from which the ball is dropped h = 110 m
Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]
From second equation of motion we know that [tex]s=ut+\frac{1}{2}gt^2[/tex]
So [tex]110=0\times t+\frac{1}{2}\times 9.8\times t^2[/tex]
[tex]t^2=22.448[/tex]
t = 4.74 second
So time taken by ball to reach the ground will be equal to 4.74 second
So option (C) will be correct answer