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Which conversion factor do you use first to calculate the number of grams of CO2 produced by the reaction of 50.6 g of CH4 with O2? The equation for the complete combustion of methane is ______

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Answer:

This is the conversion factor, we have to use:

44 g / 1mol

Explanation:

The reaction for the methane combustion is:

CH₄ + 2O₂  →  CO₂  +  2H₂O

First of all we use this conversion factor to determine the moles of methane, we used.

50.6 g . 1 mol / 16 g = 3.16 mol

So ratio is 1:1, then 3.16 mol of methane will produce 3.16 moles of CO₂

To calculate the grams of produced dioxide:

3.16 mol . 44 g / 1mol = 139.04 g