Respuesta :
Answer: [tex]3.38\times 10^{-9}[/tex] micromoles of mercury(I) chloride
Explanation:
Molarity is defined as the number of moles of solute dissolved per Liter of the solution.
To calculate the number of moles for given molarity, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in L)}}[/tex] .....(1)
Molarity of mercury(I) chloride solution = [tex]1.99\times 10^{-5}mmol/L[/tex]
Volume of solution = 170 mL
Putting values in equation 1, we get:
[tex]1.99\times 10^{-5}mmol/L=\frac{\text{milli moles of mercury(I) chloride }\times 1000}{170ml}\\\\\text{milli moles of mercury(I) chloride}=\frac{1.99\times 10^{-5}mmol/L\times 170}{1000}=0.338\times 10^{-5}mmol[/tex]
[tex]1mmol=0.001\mu mol[/tex]
[tex]0.338\times 10^{-5}mmol=3.38\times 10^{-9}\mu mol[/tex]
Thus [tex]3.38\times 10^{-9}[/tex] micromoles of mercury(I) chloride the chemist has added to the flask.
