21) Acceleration from D to E: [tex]1 m/s^2[/tex]
22) The acceleration of the bus from D to E is [tex]1 m/s^2[/tex]
Explanation:
21)
The acceleration of an object is equal to the rate of change of velocity of the object. Mathematically:
[tex]a=\frac{v-u}{t}[/tex]
where
u is the initial velocity
v is the final velocity
t is the time elapsed
In this problem, we want to measure the acceleration of the bus from point D to point E. We have:
- Initial velocity at point D: u = 0
- Final velocity at point E: v = 5 m/s
- Time elapsed from D to E: t = 21 - 16 = 5 s
Therefore, the acceleration between D and E is
[tex]a=\frac{5-0}{5}=1 m/s^2[/tex]
22) This question is the same as 21), so the result is the same.
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