Answer:
a) v = 0.006153 m^3
/kg
b) v = 0.08781 m
^3
/kg
c) v = 0.005563 m^3
/kg
Explanation:
All states are two-phase with quality given. The overall specific
volume is given by
v = vf + x vfg = (1 - x)vf + x vg
a) CO2
10◦C, 80% quality
v = 0.001161 + x * 0.00624 = 0.006153 m^3
/kg
b) H2O
4 MPa, 90% quality
v = 0.001177(1 - x) + x*0.09845 = 0.08781 m
^3
/kg
c) Nitrogen
120 K, 60% quality
v = 0.001915 + x*0.00608 = 0.005563 m^3
/kg
