contestada

1) A man decides to take out $100 per month
from his savings account. After 46
months, he has $3507 in his account.
a. Write an equation in slope intercept
which models the amount in the savings
account in terms of the number of months.
b. How much will he have after 36
months?

Respuesta :

Ashraf82

a. The equation that models the  amount in the savings  account in terms of the number of months is y = 8107 - 100 x

b. He will have $4507 after 36 months

Step-by-step explanation:

The form of the slope-intercept equation is y = m x + b, where

  • m is the slope (constant rate)
  • b is the intercept (initial amount value y at x = 0)

∵ The man decides to take out $100 per month from his

    savings account

- That means the constant rate is 100 dollars per month, that money

    will detected from his initial money every month

∴ m = 100

∴ The form of the equation is y = b - 100 x, where

  • x represents the number of the months
  • y represents the amount of money in his saving account in x months

To find the value of b substitute x and y by the given information

∵ He has $3507 in his account after 46 months

∴ x = 46 and y = 3507

∵ 3507 = b - 100(46)

∴ 3507 = b - 4600

- Add 4600 to both sides

∴ 8107 = b

∴ y = 8107 - 100 x

a. The equation that models the  amount in the savings  account in terms of the number of months is y = 8107 - 100 x

∵ y = 8107 - 100 x

∵ x = 36

∴ y = 8107 - 100(36)

∴ y = 8107 - 3600

∴ y = 4507

b. He will have $4507 after 36 months

Learn more:

You can learn more about the linear equations in brainly.com/question/9801816

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