Answer:
109.33
Step-by-step explanation:
given that the population has a distribution with a mean of 110 and a standard deviation of 8
Sample size n = 40
Std error of sample mean = std dev/square root of sample size
= [tex]\frac{8}{\sqrt{40} } \\=1.265[/tex]
From std normal distribution table we find that 30th percentile for Z is
-0.5244
Corresponding x score =[tex]110-0.5244*1.265=109.33663[/tex]
30th percentile = 109.33663
=109.33
