Respuesta :
Answer: Volume of the 1M EtOH and water should be 0.75 ml and 9.25 ml respectively to obtain the working concentration.
Explanation:
According to the dilution law,
[tex]C_1V_1=C_2V_2[/tex]
where,
[tex]C_1[/tex] = molarity of stock solution = 1M
[tex]V_1[/tex] = volume of stock solution = ?
[tex]C_2[/tex] = molarity of diluted solution = 0.075 M (1mM=0.001M)
[tex]V_2[/tex] = volume of diluted solution = 10 ml
Putting in the values we get:
[tex]1M\times V_1=0.075M\times 10ml[/tex]
[tex]V_1=0.75ml[/tex]
Thus 0.75 ml of 1M EtOH is taken and (10-0.75)ml = 9.25 ml of water is added to make the volume 10ml.
Therefore, volume of the 1M EtOH and water should be 0.75 ml and 9.25 ml respectively to obtain the working concentration
