Step-by-step explanation:
Chord AB and Chord CD are equidistant from the center of the circle.
[tex] \therefore \: chord \: AB \cong chord \: CD \\ \\ \therefore \: \frac{1}{2} \: \: AB \cong \frac{1}{2} \: \: CD \\ \\ \therefore \: EB = \frac{1}{2} \: \times 18\\ \\ \huge \purple{ \boxed{\therefore \: EB =9}}[/tex]
