Respuesta :
Answer : The partial pressure of methane is, 53.6 kPa
Explanation :
According to the Dalton's law, the total pressure of the gas is equal to the sum of the partial pressure of the mixture of gasses.
[tex]P_T=p_{H_2}+p_{O_2}+p_{CH_4}[/tex]
where,
[tex]P_T[/tex] = total pressure = 96.4 kPa
[tex]p_{H_2}[/tex] = partial pressure of [tex]H_2[/tex] = 13.5 kPa
[tex]p_{O_2}[/tex] = partial pressure of [tex]O_2[/tex] = 29.3 kPa
[tex]p_{CH_4}[/tex] = partial pressure of [tex]CH_4[/tex] = ?
Now put all the given values is expression, we get the partial pressure of the [tex]CH_4[/tex] gas.
[tex]P_T=p_{H_2}+p_{O_2}+p_{CH_4}[/tex]
[tex]96.4=13.5+29.3+p_{CH_4}[/tex]
[tex]p_{CH_4}=53.6kPa[/tex]
Therefore, the partial pressure of methane is, 53.6 kPa
Answer:
D. P = 53.6 KPa
Explanation:
Dalton's law:
- P mix = PH2 + PO2 + PCH4
∴ P mix = 96.4 KPa
∴ PH2 = 13.5 KPa
∴ PO2 = 29.3 KPa
⇒ PCH4 = P mix - PH2 - PO2
⇒ P CH4 = 96.4 KPa - 13.5 KPa - 29.3 KPa
⇒ P CH4 = 53.6 KPa