Incorrect question.The correct one is here
An airplane passenger has 100 cm³ of air in his stomach just before the plane takes off from a sea-level airport. What volume will the air have at cruising altitude if cabin pressure drops to 7.50×10⁴N/m²?
Answer:
Volume=134.7 cm³
Explanation:
Given data
Volume v₁=100 cm³=100×10⁻⁶m³
Normal atmospheric pressure P₁=1.01×10⁵ Pa
Cabin Pressure=7.50×10⁴Pa
To find
Volume v₂
Solution
From ideal gas we know that
[tex]P_{1}V_{1}=P_{2}V_{2}\\ V_{2}=\frac{P_{1}V_{1}}{P_{2}}\\ V_{2}=\frac{(1.01*10^{5} )(100*10^{-6})}{(7.50*10^{4})}\\ V_{2}=1.347*10^{-4}m^{3}\\V_{2}=134.7cm^{3}[/tex]
