Bernardo randomly picks 3 distinct numbers from the set $\{1,2,3,4,5,6,7,8,9\}$ and arranges them in descending order to form a 3-digit number. Silvia randomly picks 3 distinct numbers from the set $\{1,2,3,4,5,6,7,8\}$ and also arranges them in descending order to form a 3-digit number. What is the probability that Bernardo's number is larger than Silvia's number?

Respuesta :

Answer:Probability that Bernado's number is larger than Silvia's is 37/56

Step-by-step explanation:

Bernardo has a chance of picking 9 and he always have a larger integer.

Probability of picking 9 = 3/9 =1/3

Probability of not picking 9= 1- (1/3) = 2/3

When Bernado picks any number from 1 - 8, there is a chance of 2 possibilities.

Probability of picking 2 same numbers= 8C3

= 8×7×6/(3×2)

=56

Probability of same numbers=1/56

Number picked by Bernado is larger= 55/56

Half of these will be his.

P(larger) = 1/2 ×(55/56) = 55/112

Total Probability = 1/3 +(2/3 × 55/112)

Total Probability = 1/3 + 55/168 = 37/56