Answer:
None of these alternatives is correct
Step-by-step explanation:
Given that the mean of a normal distribution is negative.
The mean can be negative or positive.
But variance being sum of squares of each entry from mean it can never be negative
Standard deviation, by convention is taken as square root of variance.
a. the standard deviation must also be negative.
-- False.
b. the variance must also be negative.
-- False
c. a mistake has been made in the computations, because the mean of a normal distribution can not be negatived.
False mean can be negative.
None of these alternatives is correct.-- True
So last option is right.
The mean of a normal distribution is the average of the distribution.
The true statement is (d) none of these alternatives is correct.
The mean value of a normal distribution can take any of the following values
However, the variance of a normal distribution can only be positive.
The standard deviation is the positive square root of the variance.
This means that the standard deviation of a normal distribution can only be positive.
The above points mean that, options (a) to (c) are true.
Hence, the true statement is (d) none of these alternatives is correct.
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