Answer:
q = 3.87 x 10⁵ C
Explanation:
given,
Electric field, E = 8.60 x 10¹ = 86 N/C
radius of earth, R = 6371 Km = 6.371 x 10⁶ m
Coulomb constant, K = 9 x 10⁹ N · m²/C²
Charge on the earth = ?
the electric field at the point
[tex]E =\dfrac{kq}{r^2}[/tex]
[tex]q =\dfrac{Er^2}{k}[/tex]
inserting all the values
[tex]q =\dfrac{86\times (6.371\times 10^6)^2}{9\times 10^{9}}[/tex]
q = 3.87 x 10⁵ C
The electric charge on the earth is equal to 3.87 x 10⁵ C
