Answer:
E = hf or [tex]E=\dfrac{hc}{\lambda}[/tex]
Explanation:
The expression that gives the amount of light energy that is converted to other forms between the fluorescence excitation and emission events is given by :
E = hf
f is the frequency
[tex]E=\dfrac{hc}{\lambda}[/tex]
c is the speed of light
[tex]\lambda[/tex] is the wavelength
Hence, this is the required solution.
