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Two narrow slits are 0.12 mm apart. light of wavelength 550 nm illuminates the slits, causing an interference pattern on a screen 1.0 m away. Light from each slit travels to the m=1 maximum on the right side of the central maximum. how much farther did the light from the left slit travel that the light from the right slit?

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Answer:

500 nm

Explanation:

[tex]d_l[/tex] = Distance traveled by light from left slit

[tex]d_r[/tex] = Distance traveled by light from right slit

[tex]\Delta x[/tex] = Path difference = [tex]d_l-d_r[/tex]

m = Order = 1

[tex]\lambda[/tex] = Wavelength = 550 nm

Path difference is given by

[tex]\Delta x=m\lambda\\\Rightarrow d_l-d_r=1\times 550\\\Rightarrow d_l-d_r=500\ nm[/tex]

The required distance is 500 nm

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