You wish to react NO and O2 in the correct stoichiometric ratio. The sample of has a volume of 310. mL. What volume of is required (at the same pressure and temperature)?

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You wish to react NO and O₂ in the correct stoichiometric ratio. The sample of NO has a volume of 310. mL. What volume of O₂ is required (at the same pressure and temperature)?

Answer : The volume of O₂ required at STP is, 0.155 L

Explanation  Given,

Volume of NO = 310 mL = 0.310 L     ( 1 L = 1000 mL)

The balanced chemical reaction will be:

[tex]2NO+O_2\rightarrow 2NO_2[/tex]

By the stoichiometry we can sat that, 2 moles of NO react with 1 moles of O₂ to give 2 moles of NO₂.

At STP, 1 moles of a gas occupies 22.4 L volume of gas.

In terms of volume we can say that:

As, [tex]2\times 22.4L[/tex] volume of NO combine with 22.4 L volume of O₂

So, [tex]0.310L[/tex] volume of NO combine with [tex]\frac{0.310}{2\times 22.4}\times 22.4=0.155L[/tex] volume of O₂

Thus, the volume of O₂ required at STP is, 0.155 L