This is an incomplete question , her is a complete question.
You wish to react NO and O₂ in the correct stoichiometric ratio. The sample of NO has a volume of 310. mL. What volume of O₂ is required (at the same pressure and temperature)?
Answer : The volume of O₂ required at STP is, 0.155 L
Explanation Given,
Volume of NO = 310 mL = 0.310 L ( 1 L = 1000 mL)
The balanced chemical reaction will be:
[tex]2NO+O_2\rightarrow 2NO_2[/tex]
By the stoichiometry we can sat that, 2 moles of NO react with 1 moles of O₂ to give 2 moles of NO₂.
At STP, 1 moles of a gas occupies 22.4 L volume of gas.
In terms of volume we can say that:
As, [tex]2\times 22.4L[/tex] volume of NO combine with 22.4 L volume of O₂
So, [tex]0.310L[/tex] volume of NO combine with [tex]\frac{0.310}{2\times 22.4}\times 22.4=0.155L[/tex] volume of O₂
Thus, the volume of O₂ required at STP is, 0.155 L