Answer:
The work required to stretch the spring from 1.1 meters to 1.5 meters is equal to 5.2 joules
Explanation:
Given that,
Force acting on the spring, F = 2 N
The spring compresses from 1 meter (its natural length) to 0.8 meters
The force acting on the spring is given by :
[tex]F=-kx[/tex]
[tex]2=-k(0.8-1)[/tex]
k = 10 N/m
Let W is the work required to stretch the spring from 1.1 meters to 1.5 meters. It is given by :
[tex]W=\dfrac{1}{2}k(x_2^2-x_1^2)[/tex]
[tex]W=\dfrac{1}{2}\times 10\times (1.5^2-1.1^2)[/tex]
W = 5.2 Joules
So, the work required to stretch the spring from 1.1 meters to 1.5 meters is equal to 5.2 joules. Hence, this is the required solution.
