Answer: Option 'A' is correct.
Step-by-step explanation:
Since we have given that
In 80 ounces, 10 ounces of gold.
So, Proportion of gold would be
[tex]\dfrac{10}{80}\times 100=12.5\%=0.125[/tex]
In new alloy of 5 ounces, one fifth of ounce is gold, so, it becomes,
it means 0.2 ounce is gold in 5 ounces.
So, proportion of gold would be
[tex]\dfrac{0.2}{5}\times 100=4\%=0.04[/tex]
Let x be the amount of silver is to be added.
According to question, it becomes,
[tex]0.125\times 80=0.04(80+x)\\\\10=3.2+0.04x\\\\10-3.2=0.04x\\\\6.8=0.04x\\\\x=\dfrac{6.8}{0.04}\\\\x=170\ ounces[/tex]
Hence, Option 'A' is correct.