Respuesta :

Answer:

The answer to your question is below

Explanation:

Data

Mass of SO₂ = 75 g

Atoms of HCl = ?

Write the balanced reaction

                   SO₂  + Cl₂  +  2H₂O   ⇒  H₂SO₄   +   2HCl

Process

1.- Calculate the molecular mass of SO₂ and HCl

Molecular mass SO₂ = 32 + (16 x 2) = 64

Molecular mass of HCl = 36.5

2.- Calculate the mass of HCl formed

                    64 g of SO₂   -----------------  2(36.5) g of HCl

                     75 g of SO₂  ----------------  x

                      x = (75 x (2 x 36.5)) / 64

                      x = 5475/64

                      x = 85.54 g of HCl

3.- Calculate the number of atoms of HCl

                      36.5 g of HCl -------------------- 6.023 x 10²³ atoms

                       85.54 g of HCl ----------------- x

                       x = (85.54 x 6.023 x 10²³) / 36.5

                       x = 1.41 x 10²⁴ atoms

12.-

a) Calculate the molecular mass of H₂SO₄

Molecular mass = (2 x 1) + (32 x 1) + (16 x 4) = 98 g

               64 g of SO₂ -------------------- 98 g of H₂SO₄

                75 g of SO₂ --------------------  x

                  x = (75 x 98) / 64

                  x = 114.8 g of H₂SO₄

               98 g of H₂SO₄ ------------------- 6.023 x 10²³ atoms

            114.8 g of H₂SO₄ ------------------- x

                  x = (114.8 x 6.023 x 10²³) / 98

                  x = 7.06 x 10²³ atoms of H₂SO₄

13.-

          2NaNO₃  +   CaCO₃   ⇒   Na₂CO₃  +  Ca(NO₃)₂

Process

1.- Calculate the molecular mass of CaCO₃

CaCO₃ = (40 x 1) + (1 x 12) + (16 x3) = 100 g

2.- Convert 7 g of CaCO₃ to moles

                    100 g  ------------------- 1 mol

                        7 g --------------------  x

                        x = (7 x 1) / 100

                       x = 0.07 moles

3.- Calculate the moles of NaNO₃

                     2 moles of NaNO₃  ------------- 1 mol of CaCO₃

                      x                             --------------- 0.07 moles

                      x = (0.07 x 2)/1

                     x = 0.14 moles of NaNO₃