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Which equation represents a line passing through the point (-5, 1) and PARALLEL to the line given by y = 3x - 4

y -1 = -1/3 (x + 5)
y + 5 = 3(x - 1)
y + 1 = -1/3(x - 5)
y - 1 = 3(x + 5)

Respuesta :

option (D)

(y-1)=3(x+5)

Step-by-step explanation:

Given the line passes through the point (-5,1) and parallel to the line

y= 3x-4

The slope of above line is = 3

Therefore the slope of the required straight line is m=3

The equation of a straight line is

[tex](y-y_1)=m(x-x_1)[/tex]

⇔(y-1)=3(x+5)     [ [tex]x_1=-5[/tex] and [tex]y_1 =1[/tex]]

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