Explanation:
(a) Frequency of radar energy, [tex]f = 10\ GHz =10^{10}\ Hz[/tex]
The relation between frequency and wavelength is given by :
[tex]c=f\lambda[/tex]
[tex]\lambda=\dfrac{c}{f}[/tex]
[tex]\lambda=\dfrac{3\times 10^8}{10^{10}}[/tex]
[tex]\lambda=0.03\ m[/tex]
or
[tex]\lambda=3\ cm[/tex]
(b) If wavelength, [tex]\lambda=25\ cm=0.25\ m[/tex]
[tex]c=f\lambda[/tex]
[tex]f=\dfrac{c}{\lambda}[/tex]
[tex]f=\dfrac{3\times 10^8}{0.25}[/tex]
[tex]f=1.2\times 10^9\ Hz[/tex]
or
f = 1.2 GHz
Hence, this is the required solution.
