During the reaction, 3.50 μmol of HCl are produced. Calculate the final pH of the reaction solution. Assume that the HCl is completely neutralized by the buffer.

Respuesta :

Answer:

The pH of the solution will be equal to 5.46

Explanation:

The dissociation reaction of HCl is equal to:

HCl → H+ + Cl-

To solve the exercise we must first convert the µmoles to moles using the following conversion factor:

3.5µmoles x [tex]\frac{1 mol}{1x10^{6} umol}[/tex] = 3.5x[tex]10^{-6}[/tex]moles

Assuming a liter of solution, we can calculate the molar concentration by:

M = [tex]\frac{Number of moles}{Liter of solution}[/tex]

Replacing:

M = [tex]\frac{3.5x10^{-6}moles }{1 L}[/tex] = 3.5x[tex]10^{-6}[/tex]moles/L

As this acid dissociates completely, the concentration of protons and chloride will be equal to 3.5x[tex]10^{-6}[/tex]moles/L

The pH will be equal to:

pH = -log[H+]

Replacing:

pH = -log[3.5x[tex]10^{-6}[/tex]] = 5.46

The pH value of reaction solution is 5.46

The acid HCl breaks into hydrogen and chlorine.

    HCl ⇒ H⁺ + Cl⁻

As we know that,  [tex]3.50\mu mol=3.5*10^{-6} moles[/tex]

The Molarity of solution is,

               [tex]M=3.5*10^{-6}moles/liter[/tex]

The pH value is given as,

                  [tex]pH=-log[H]\\\\pH=-log[3.5*10^{-6} ]\\\\pH=5.46[/tex]

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