Step-by-step explanation:
If the order of the objects doesn't matter (ABC is considered the same as CBA), then the number of combinations is:
₈C₃ = 8! / (3! (8−3)!) = 56
If the order does matter (ABC is considered different than CBA), then the number of permutations is:
₈P₃ = 8! / (8−3)! = 336
