Answer:
C
Step-by-step explanation:
Since CB is a tangent to the circle then ∠ ABC = 90°
Using Pythagoras' identity in the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, thus
AC² = 5² + 8² = 25 + 64 = 89 ( take the square root of both sides )
AC = [tex]\sqrt{89}[/tex] → C
