Answer:
62_grams of FeO
Explanation:
Molar mass of Fe = 55.845_g/mol
Molar mass of O2 = 15.999_g/mol
From law of conservation of mass
2 moles of Fe combines with one mole of O2 to form 2 moles of FeO
Number of moles of Fe and O2 present = mass/(molar mass) = 56/55.845~1
and 24/16 = 1.1.5
Therefore
1 part of Fe will react with 0.5 part of one mole of O2
which is 54_g of Fe reacts with 8_g to form 54+8 = 62_grams of FeO
