A ruler of length 0.30m is pivoted at its centre. Equal and opposite forces of magnitude 2.0N are applied to the ends of the ruler, creating a couple which create an angle of 50o with the ruler. What is the magnitude of the torque of the couple on the ruler.

Respuesta :

This question involves the concepts of the torque, moment of couple and moment arm.

The magnitude of the torque of the couple on the ruler is "0.38 N.m".

The torque produced by the couple also known as moment of couple is given by the following formula:

[tex]Torque=T=(Force)(Moment\ Arm)[/tex]

where,

moment arm = perpendicular distance between line of action of both forces = (0.3 m)Cos 50° = 0.19 m

Therefore,

[tex]T=(2 N)(0.19\ m)[/tex]

T = 0.38 N.m

Learn more about moment of couple here:

https://brainly.com/question/24551104?referrer=searchResults

The attached picture shows moment of couple.

Ver imagen hamzaahmeds