Answer:
N2 + 3 H2 => 2 NH3
Rate of reaction = -d[N2]/dt = (-1/3) x d[H2]/dt = (1/2) x d[NH3]/dt
Rate of production of ammonia = d[NH3]/dt
Rate of consumption of hydrogen = -d[H2]/dt
From the equations above:
(1/2) x d[NH3]/dt = (-1/3) x d[H2]/dt
d[NH3]/dt = (2/3) x (-d[H2]/dt)
Thus the relationship is:
Rate of production of ammonia = (2/3) x Rate of consumption of hydrogen
